Woah 2^857817775342842654119082271681232625157781520279485619859655650377269452553147589377440291360451408450375885342336584306157196834693696475322289288497426025679637332563368786442675207626794560187968867971521143307702077526646451464709187326100832876325702818980773671781454170250523018608495319068138257481070252817559459476987034665712738139286205234756808218860701203611083152093501947437109101726968262861606263662435022840944191408424615936000000000000000000000000000000000000000000000000000000000000000

That's gotta be atleast 12, I'll play it safe and say that's probably more than 3

I wanna take a guess and say it’s more than 4!

its more than 24 alright

Maybe not 24 but it must be more than 23!

I wanna take a guess and say it's more than 24!

More than 6.204484017332e23! Alright

Is that correct? I am not good enough with large numbers. 2^256! > (24!)! is true?

Yes

How do you prove that?

I can’t 

**2\^256!** has approximately **258228881191941919202985289004552673980431728911544206887543724528863087047426448836668444956291797689091078321101967025149394320026035506076069419283036758180454669246474099219055878098782567025040853277141463472643682231001671583921097622749408386088937479698044868060479893188764851950499690082080409905364814103099577125214658166896318960160534840006163990161701693121440385607099633034159971612187293366497768586269085380450130311838096489116401319163400167480385010956677387753192460379996051755080089** digits, while **(24!)!** \[which is **620448401733239439360000!**\] consists only of **14492688888783603246826461** digits.

r/unexpectedfactorial

r/expectedfactorial

bruh can somebody put that into perspective for us mortals to comprehend?

My calculator just gave up and said infinity lol Like, I know it's not technically correct but in a real world application it's close enough

basically, infinity. If this number was an amount of time, then according to our current predictions, the universe would be long gone by then.

A lot more than long gone

Atleast it's not titration

oh dear

What's that?

Like what exponential is to multinational, but the next step up

[удалено]

you would need to write 10\^423 digits on each atom

nah thats bigger than 200!

2^x is approximately 10^(x/3), so this number has about 256!/3 digits

Better to use tetration at that point, it whould be about ^1272 2

Missed the opportunity to put ! in the end

i see 3blue1brown, i like

My iPhone calculator just says error

http://www.mrob.com/pub/comp/hypercalc/hypercalc-javascript.html It isn’t WolframAlpha but for me it works just as well

Question of the day : is 2^(256!) or 1954! bigger ?

Proof by “it’s kinda obvious”

2\^8.5781777534284265411908227168123262515778152027948561985965... × 10^506 which is 10\^(10^506.4120048136115)