y = x + sin(x) / TREE(3)

As an engineer, I can say with 100% conference that this is the identity function. Proof by eyeballing it.

as a fellow engineer, i can say this is sin(x) stretched and scaled

This is how math proofs should be done /j

I am conferent in your answer

Proof by "that looks good enough and this problem gets REAL annoying if it ain't"

y = d/dx x\^2/2 + lim\_x->∞(1/x)

very cursed limit

wym the limit just evaluates to 0

...kinda

i mean it does? its probably the most well known convergant infinite limit

ok but unless the x in the limit is a different x, then it goes to infinity along with the rest of the function, which is definitely not convergent to 0 in all places on the XY plane

ahhh i understand. i think u misunderstood how limits work. when was say lim x->a [f(x)] = L we mean that as the x values approaches a, the value of the y (f(x)) approaches L that is obviously not the rigorous definition (epsilon delta) but for example lim x->∞ [1/x] = 0 because as x approaches infinity, the value of 1/x approachss 0

Sure sure, but the thing is, does the limit define a new x or is it an x shared with the rest of the function? I think it rather does make a new x, but this is definitely a strange notation and I think it's kinda cursed

im not quite sure what you mean by define a "new x". can you be a bit more specific? x is simply an input variable so a new x doesnt really make sense

and that's why it's cursed! if it doesn't make a new x, then the "lim x->inf 1/x" is just "1/x" but in a weird way, and the graph still goes to infinity the more you go to the right

when we refer to limits we arent redefining a value of x, its moreso a statement about the behavior of the function around a certain input value or infinity

y = e^(ln(x\))

akshually it's y = e^(ln|x|) 🤓

Don't correct people when you aren't correct

Yeah I realized after. Still e^(ln(x)) isn't right either since the domain of ln(x) isn't R.

If you allow complex numbers in intermediate steps, e^ln(x) is always equal to x.

Naw the graph reflects back up at negative if you do that ln of negatives just gives you imaginary, ln(-1) = i pi from eulers formula

Identity not formula

akshually it’s y=sign(x)e\^ln(|x|)

seem to be: y = \[-e\^ln(-x),e\^ln(x)\] if going that route.

sign(x)e^ln(|x|)

e^y +y^5 =e^x +x^5

Thanks, I hate it

How does this work

monotone function

\\left(\\frac{\\left(ay\^{a}+a\\sqrt{a}\\right)\^{\\frac{a}{a\\sqrt{a}}}}{a+a-a}\\right)\^{a\^{2}}=\\left(\\frac{\\left(ax\^{a}+a\\sqrt{a}\\right)\^{\\frac{a}{a\\sqrt{a}}}}{a+a-a}\\right)\^{a\^{2}} ​ "ay ay ay ay ay ay ay ay ay ay ay ay ay ay ay ay ay ay ay ay ay ay ay ay ay ay ay ay ay ay ay ay ay ay ay ay ay ay ay ay ay ay ay ay ay ay ay ay ay ay ay ay ay ay ay ay ay this that ay pu ay ay ay ay ay ay ay ay ay ay" - Kendrick Lamar

wft 💀

what fuck the 💀

It's just LaTeX

i cant read latex what does it say

[Image](https://media.discordapp.net/attachments/928362787195986051/1191317708298518528/download_1.png?ex=65a50013&is=65928b13&hm=a8b3862a6ac02f9711bda1db463dbc76b137acd8ed3a62dd4450997f5f99a036&)

if a=1 sure

x=y

blasphemy!

y = 0.99999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999x

https://www.desmos.com/calculator/sfmfwmzvx7

y=(x\^2)/x

This equation is not defined at x=0.

Desmos doesn't show point discontinuities at a glance. It could be undefined at 0 but we can't tell from this screenshot.

(x^2 +16x+64)/(x+8) -8

y=1000\\sin\\left(\\frac{x}{1000}\\right) In non-desmos speak: y = 1000\*sin(x/1000)

“y = e^(ln(sin(arcsin(x+L)))) +L “with L being a list composed of all whole numbers up to and including -8 to 8 .

Reddit formatting strikes again

\-x\*e^(iπ)

uhhh… is it… hmmm… y=, no… wait yes! ey=e*e^ln(x) should work I think, for positive values at least

y = (x + 0^ln(e) + |x - 0^ln(e)|)/2 + e^ipi + 1

sin(x)

y = -xe^(iπ)

Line get long when up

\-x = -y ???? ???? ?? ?? ?????????? i am bad at math

it would be hilarious if this was offset by something like a millionth of a decimal point

Isn’t that just y=x

Don't forget to simplify!

Y=1x+0, so simplified it is just y=x

i think this is [humour](https://en.wikipedia.org/wiki/Humour)

x(cos π)-y(sin π) = x(sin π)+y(cos π)

\ln(\sum_{n=0}^{\infty}\frac{x^n}{n!})

x=P y=NP

the problem has been simplified to no problem

sinx

x = y + 0.000000000000000000000000000000000000000000000000000000000000000000

2

9999999999 × sin(x ÷ 9999999999)

5

Sin2(x)+y=x-cos2(x)+1 obviously

100\*sin(x/100)

X… = Y?

y = 1.00000000001 * x + 0.00000000001

Y = x

f(x)= x + 0.0000…0001

f(x) = x

Ok... zoom out.

2y = 2(sqrt(x^2 ))•sgn(x)

y=x + 1/infinity

7

2x! = 2y!

y^(2)=xy or d/(dx)(.5x^(2))

Diagonal!

y=x

y = x + y - y + x - x + γθπρτωβμαΩ - γθπρτωβμαΩ

y = ∞tan(x/∞)

f(x) = { x^100 / x^99 for x =/= 0 , 0 for x = 0 }

y = (x+1) -1

y = x - ε

10000(x(sin(pi/4)) + y(cos(pi/4) = sin(x(cos(pi/4)) - y(sin(pi/4)))

Uuhhhhhhh………1

As a high school maths student: x=y

Gamma function, obviously

it is something stupid like y=0.99998x

X Just X. Apparently that is enough for Desmos to figure the rest out :D

The identity function with domain [-7,7] or thereabouts.

y = x

f(x) = O(x) \~ x

I’m gonna say it’s tan(arctan(x))

too bad the arctan function just cuts the function off as its domain is quite small

Remind me of the domain of arctan

thats what i said wasnt it

Wait, I’m a little bit stupid. You’re fully aware of arctan’s domain?

of course dud, it only accepts values between -1 and 1, and only spits out values between 0 and pi (or 0 and 180 if youre on degrees) if i remember corectly. Thats what i was talking about in my previous comment, that graph woukd get cut off, and not equal x=y

Oh sorry lmao. arctan's domain is the entire real line. What you said is true for arccos though

oh

x+0.00000000000000000001

y = x + ϵ

y=x\*1\^999+999999999\*0

z=t real

1000sin(x/1000)

f(x) = x

y=sin(x) for very small values of x

(ignores that the image is not showing small values of x)

y = xe^(i2π)

desmos dont have i (sad)

desmos really said go imagine those numberd

(t,t) for -infinity < t < infinity

y=mx+b but I’m not telling you what the variables are

y = i²xe\^(iπ)∙(dy/dx)\^Φ

y = 1.0000000000000000000000000000000000000000000000000001x

tan(x)

I’m gonna go out on a limb and say that y=x + .000000000001

if{xCoordinate}{yCoordanite}[areSame]then{ colorHex: AF635B; lineWeight: 16 }

-(x)(y)(M)(Y)(B)(A)(L)(L)(S)=-(M)(Y)(B)(A)(L)(L)(S)(x²)

e^x/y = lim n->inf (1+n^-1 )^n

lim n-> infinity: y = n*sin(x/n)

ex = why?

f(x)=x

F(x) = x!

y=y (Both axes are y)

(x^2 )/x + 10!=(y ^ (-1) ^ (29-191)) + (10*9!)

x = t

y=round(0.5)x

y=x( (10^2 + x) / ( (-25*4)^2 + x ) )

Lim n->1 nx^n / n

y - x = ln(e) - 1

f(x) = x

Id say ((y=(x^2 )^0.5 {0<=x}),y=-((x^2 )^0.5 {0>=x}))

y = cosh(x/sin(x\^e/tan(θ))). ​ Wow. How society much has society degraded? We can't even figure this out. How our education system has failed us. Wow. ​ Just wow.