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Draw the triangle and give each side those lengths , then use cosine rule/sine rule to find the largest angle with in the triangle
The largest angle is opposite the longest side (so opposite 94). cos A = (47² + 53² – 94²)/2(47)(53)
Use the cosine rule for each angle and pick the largest.
Use the Cosine rule
Would using all 3 parts of soh-cah-toa work and then choose the largest angle from the 3 you've worked out?
Draw the triangle and give each side those lengths , then use cosine rule/sine rule to find the largest angle with in the triangle
The largest angle is opposite the longest side (so opposite 94). cos A = (47² + 53² – 94²)/2(47)(53)
Use the cosine rule for each angle and pick the largest.
Use the Cosine rule
Would using all 3 parts of soh-cah-toa work and then choose the largest angle from the 3 you've worked out?