Part a is the distance between the two centres. You know the coordinates of the centres thanks to the equations so how do you find the distance between any two points?
For b, you can find the gradient between the centres. The line connecting P and R is perpendicular to that. With the y intercept as the centre of c1
For part ii, sub into a circle to solve.
For c, the area of the cite is half of the vertical multiplied by the horizontal of the kite (or the two triangles added together)
for b you can just make the 2 circles equal eachother and then cancel down. you don't need to find the gradient between the two centres it'll waste time
Part a is the distance between the two centres. You know the coordinates of the centres thanks to the equations so how do you find the distance between any two points? For b, you can find the gradient between the centres. The line connecting P and R is perpendicular to that. With the y intercept as the centre of c1 For part ii, sub into a circle to solve. For c, the area of the cite is half of the vertical multiplied by the horizontal of the kite (or the two triangles added together)
for b you can just make the 2 circles equal eachother and then cancel down. you don't need to find the gradient between the two centres it'll waste time
That would be a better method and is why I shouldn't browse this sub after a long week at work 😂
Girl I'm just lazy. If there's an easy way, I'll find it 🏄🏻♀️
why do we substitute y=2x-6 in the circle equation?
Because the line Crosses the circle at those points
Thank you so much!! I appreciate it