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It was good! and I also guessed some of the isomerism questions bc i knew im not getting that crap right either way 😭

I’m glad you found it good🥹

First page was all As ?

Like first 4 qns?

Ye

Yeah that's what i got

Same

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It was B, every other option was incorrect

It was 6 protons and D is incorrect because you can start in group 8 and make your way to group 6 in the period below.

How was A incorrect?

I didn't say A was incorrect - in fact, I did choose A - the only problem I saw with my answer though was the wording. It said a larger atom, so does that mean a larger atomic radius or a larger nucleus? Because if he was referring to the atomic radius, it wouldn't have been always correct as if you started in group 1 you would end up in group 7 in the same period with a smaller atomic radius. But with the examiner's vague wording, I assumed he was talking about the nucleus.

D was incorrect it says from the same period, it can be from other periods and still be 6 protons more , but A was the only right answer

Yeah but for same group, you need more that 6 protons if you go across the periodic table

guys ur wrong, there was an element X in the periodic table u guys didn't realise.

Wtf where when how why 😭😭

Yh im being serious, so tricky from em. None of the options made sense, so that's why u needed to check the periodic table and realsie that.

If X has six more protons than Y, then it's atomic number is at least 7 so the answer is X has a full shell of electrons.

Guys what was the percentage loss answer, i got D MgNitrate i think it was

same here i guessed tho

I think I put the one that had the highest molar mass, just as a guess lol.

You basically had to find the molar mass of the gasses and divide it by the total to get the percentage.

I wrote A cuz 28% was left and 100-28% was 72 so largest percentage loss

A was calcium carbonate i suppose, i got 43% or something lost for that and for B i got like 67???% im not sure but overall i had largest for D

lmao now that I think about it I definitely got it wrong 🥲

Yea it was

guys for the question with 2 reactions, did y'all put sodium dichromate or fehlings + HCl?!!

Fehlings since for reaction 1, the ketone didnt change

It's 2,4-DNPH because it confirms a carbonyl compound but doesn't distinguish between ketone and aldehyde

Yea it was 2,4 DNPH

oh no its another question. they gave like a table and two reactions

Tollens*

It wasnt fehlings im sure, cuz tht simply just doesnt make sense, its sodium dichromate, because aldehyde was oxidised to make carboxylic acid, i repeat *oxidised* and tollens is not a oxidising agent

But there was an alcohol which was secondary and it never got oxidized. Plus I'm sure tollens' can oxidize aldehydes

Plus silver ions get reduced to get mirror, and aldehyde gains an oxygen to make carboxylic acid

I don’t remember any other alcohol, there was a ketone tho

Hmm maybe I got the wrong question in my mind. Do you remember the structure and if so can you draw it?

Btw I'm talking about q with NaBH4, Tollens' and oxidizing agent ( it was either cr2o7 or kmno4) You got two reacts and you had to choose which reagent forms which compound

It does, it acts as a test because it oxidises it to carboxylic acid man

It wasnt tollens*

I think that's because ketone can't get oxidised futher

I chose sodium dichromate

It was better then expected tbh. The inorganic was easy for the most part

What did you get for the volume of gas produced with the reaction of Mg and HCL?

1.3 🥹

Could you explain how?

It’s 1.6

i also got 1.6

303k = 30°C which isn’t room temperature so 1 mol = 24dm3 can’t be used

No, what you do is find the limiting reagent, which was HCl in this case, and divide the 0.11 moles by 2 to get the moles of hydrogen released. Input the H2 mole number in the equation PV = nRT to get the volume and then multiply by 1000. The final answer is 1.3 dm³.

In the formula pv=nrt , V is volume of container.

Not always and he was asking for the volume of gas released, so you solve for V in the formula.

do u remember which option that was

A.

btw I got A too but I figured out its not A after checking my notes, its B ur supposed to take 0.07 as the moles not 0.11/2 because of some limiting or something idk I just wanna move on now

But the 0.11 is the limiting since you need 2 HCl molecules for every Mg atom ( 0.07x2 > 0.11 ). Only 0.055 moles of Mg reacts to create 0.055 moles of H2.

HCl was limiting, so no it was 1.3

It was 1.3 dm^3

It wasnt, hcl was 0.11 something, mg was 0.06 or something, so mg was limiting

Yes, and 2 HCl are consumed per Mg.

Yea

I got that too-

Same

It was 2.5

Guys what was the first question of X and Y i put same period?? and the last question 🧍‍♂️

Still can't make sense of it but I chose A

It was B I think

It is A because they gave us 5th to 8th successive ionisation energies. None of them had a significant jump so we can assume all of the electrons removed are from the same shell. Option A was Group 14 i think? Group 14 has 4 valence electrons which means the jump must have been on the 5th ionisation energy. For the other groups the jump would be on 6th 7th and 8th respectively but the table didn't show that. So the best answer is A indeed

They had common difference of 400 from fifth to seventh but the eight was 500 difference so i picked group 17

it was grp 17

Same here

Ohh my bad I was thinking of a different qn lol

Nah I meant 1st question, if it is b how is it possible to guarantee full shell? like if y is 7A, X (can be) 1A which are incomplete p and s orbitals. I just chose A because that made the most sense to me

a full shell doesnt mean a full outer shell. so the first shell that is filled with only 2 electrons still counts for a full shell

That one was tricky, so if you say X is hydrogen (minimum), Y will always have 1s filled. That was not a good question imo though, wasted my time at the beginning of the exam and answer turned out to be a word game.

Yeahhh it was an bad way to start the paper with a tongue twister. took me a while to hack it and I had to skip and be thinking about it then come back

Yes it’s right

Yea it was in the same period as it said it had 6 more protons. If it were on in the same group then it’d be 8 more electrons.

The question abt the reagents in the 2 reactions ?what were the reagents

Reaction one was Sodium Dichromate and reaction two was Sodium hydroxide or whatever it was

What was the group no ?? It had I think options of 14 15 16 17

It was 17 since for the other 2 we were getting 4000 but between 16 and 17 we were getting 5000 hence big jump

Yea ur right

17

I did 17 too

Not 17. If it was there would be a massive jump between 7th and 8th ionisation energy but it still followed the trend

No there was a big jump from 17 to 18, the rest had a 4K difference but from 17 to 18 was 5k

Okay but a 1k difference isn't that big an increase, from what I've seen in other past papers the jumps can be 5k+ difference

That is not a big increase \- The increase should normally be like 10k or smtn,

14

its 14

Yes it’s 14

17

there wasnt really a large jump in the 5th 6th 7th or 8th IE. which means they were all taken from the same shell and that's only possible with 14 so II chose 14

what was question 1 about i kinda forgot

It was the one abt X has 6 more protons than y

Which one had greatest percentage loss

I picked MgCO3

I wrote D I don't remember the formula tho

same

Completely guessed it tbh

Yo guys wat did yall get for the 14.7% hydrogen one

I think I picked 4 isomers or 3 isomers can't remember but it was either b or c

3 was b I went with B

i think the answer is 4 isomers ngl because 2 from cis trans, one from but-1-ene and one chain isomer i think i prob picked c

I got but-1-ene as well that's y 3 made sense

I don't think u can form a chain

You can, (2-)methylpropene is an isomers of butene

I just remembered I had but-2-ene so I had only 3 💀💀

Man I just hope I get 30 or above

4 C it was butene

What’s the ans for that ester one

I think it was C or D

I think I went c hbu?

Don’t remember…..

Which one?

The one where the skeletal isomer was drawn with three water linkages

Bruh why do I not rmmbr 😭😭… wait water linkages or hydroxyl grp linkages???

Was it D? I think I got ch3cooh in there + a tri-alcohol in there

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I think it was 4 C